Matematika Sekolah Menengah Atas 1.
[tex]7 {}^{3} = [/tex]

2.
[tex]3 {}^{3 } + 2 {}^{3} = [/tex]

3.
[tex]5 {}^{3} - 2 {}^{3} [/tex]
4.
[tex]4 {}^{3} \times 3 {}^{3} = [/tex]
5.
[tex]12 {}^{3} \div 4 {}^{3} = [/tex]
[tex]\colorbox{black}{\purple{\boxed{ \tt{ \color{green}{good luck}}}}}[/tex]

1.
[tex]7 {}^{3} = [/tex]

2.
[tex]3 {}^{3 } + 2 {}^{3} = [/tex]

3.
[tex]5 {}^{3} - 2 {}^{3} [/tex]
4.
[tex]4 {}^{3} \times 3 {}^{3} = [/tex]
5.
[tex]12 {}^{3} \div 4 {}^{3} = [/tex]
[tex]\colorbox{black}{\purple{\boxed{ \tt{ \color{green}{good luck}}}}}[/tex]

Jawaban :

7³ = 7 × 7 × 7

= 49 × 7

= 343

3³ + 2³ = (3 × 3 × 3) + (2 × 2 × 2)

= (9 × 3) + (4 × 2)

= 27 + 8

= 35

5³ - 2³ = (5 × 5 × 5) - (2 × 2 × 2)

= 125 - 8

= 117

4³ × 3³ = (4 × 3)³

= 12³

= 1.728

12³ ÷ 4³ = (12×12×12) ÷ (4×4×4)

= 1.728 ÷ 64

= 27

Perpangkatan adalah perkalian antara suatu bilangan dengan bilangan itu sendiri atau bisa disebut perkalian berulang ulang

Jawaban:

= 7 × 7 × 7

= (7 × 7) × 7

= 49 × 7

= 343

3³ + 2³

= (3 × 3 × 3) + (2 × 2 × 2)

= (9 × 3) + (4 × 2)

= 27 + 8

= 35

5³ - 2³

= (5 × 5 × 5) - (2 × 2 × 2)

= (25 × 5) - (4 × 2)

= 125 - 8

= 117

4³ × 3³

= (4 × 3)³

= 12³

= 12 × 12 × 12

= (12 × 12) × 12

= 144 × 12

= 1.728

12³ ÷ 4³

= (12 ÷ 4)³

= 3³

= 3 × 3 × 3

= (3 × 3) × 3

= 9 × 3

= 27

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